how much power is consumed by a load drawing 5 a with 120 v across it
How much power is consumed by a load drawing 5 a with 120 v beyond it?
one answer:
Answer:
600 West
Caption:
The power consumed past a load (resistance) is given past
where
P is the power
V is the voltage
I is the current
For this load, we take:
5 = 120 V
I = 5 A
Substituting,
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Answer:
The time constant is 0.26 s
Explanation:
From ohm's law,
Electric current (I) = potential departure ÷ resistance = xi.1 ÷ 3.xix = iii.48 A
Quantity of electricity (Q) = capacitance × potential deviation = 81.9×x×^-iii × 11.1 = 0.90909 C
time constant (t) = Q/I = 0.90909/three.48 = 0.26 s
Answer: The answer is D! Hope this helps!
Explanation:
Respond:
a. 4d.
If the auto travels at a velocity of 2v, the minimum stopping distance will be 4d.
Caption:
Hullo there!
The equations of altitude and velocity of the automobile are the following:
x = x0 + v0 · t + 1/2 · a · t²
five = v0 + a · t
Where:
x = position of the motorcar at time t.
x0 = initial position.
v0 = initial velocity.
t = time.
a = acceleration.
v = velocity of the car at fourth dimension t.
Let´s discover the time information technology takes the machine to end using the equation of velocity. When the automobile stops, its velocity is zippo. Then:
velocity = v0 + a · t v0 = v
0 = v + a · t
Solving for t:
-five/a = t
Since the acceleration is negative considering the car is stopping:
5/a = t
Now replacing t = five/a in the equation of position:
x = x0 + v0 · t + 1/2 · a · t² (let´due south consider x0 = 0)
x = v · (v/a) + 1/2 · (-a) (v/a)²
10 = five²/a - 1/2 · v²/a
ten = 1/two five²/a
At a velocity of v, the stopping distance is 1/2 v²/a = d
Now, permit´southward practise the same calculations with an initial velocity v0 = 2v:
Using the equation of velocity:
velocity = v0 + a · t
0 = 2v - a · t
-2v/-a = t
t = 2v/a
Replacing in the equation of position:
x1 = x0 + v0 · t + 1/2 · a · t²
x1 = 2v · (2v/a) + one/2 · (-a) · (2v/a)²
x1 = 4v²/a - 2v²/a
x1 = 2v²/a
x1 = 4(1/2 five²/a)
x1 = 4x
x1 = 4d
If the car travels at a velocity 2v, the minimum stopping altitude volition be 4d.
Answer:
A. Mass(but)
Explanation:
The right respond is A because if the balloon is filled with air, it'south filled with matter . Matter is anything that has space and occupies mass . The air occupies mass in the balloon but that doesn't hateful that the balloon is heavier . People misfile themselves with mass and weight saying it means the same thing . Mass , like I said is the amount of thing an object contains whereas weight is how much an object weighs .
And so what the thermal energy equation tells y'all is the internal heat free energy a organization gives you lot due to the motion of particles/temperature. This estrus is due to the kinetic energy in the particles. Q represents the heat transfer of a material that has a specific mass, m, specific heat, c, and some temperature or change in temperature, ΔT. For example, say you have an object of mass 1kg, specific rut 0.5J/kg°C and the temperature changes from 50°C to 100°C. To observe the rut transfer you would use the equation Q= 1kg*0.5J/kg°C*(100°C-50°C). This would tell you that the heat transfer of this particle is 25J which means that 25J of energy are transferred from one point to the other in this organization.
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